[LC++]couple of questions (was: Re: testing)

[Mark Phillips]

Carlo Wood wrote:
> 
> this is not an array, so you should be using operator[].
> this[i] is nonsense.

Okay, I think I know where I went wrong.  My understanding is that with 
an array, "int myArray[30];" for example, then "myArray" refers both 
to the entire array and to a pointer to myArray[0].  So there is a 
degree of ambiguity.  Now an object can be made to look like an array, 
using "operator[]".  My thought was that perhaps this same type of 
ambiguity was available for objects made to look like an array.  But
where I am probably getting confused is that myArray is a pointer 
to "int", not a pointer to "myArray[30]", which is the equivalent of 
what "this"
points to.

Cheers,

Mark.