[LCP]which one first?

[Vincent Penquerc'h]

> > for(i = 0; buf[i] != ' ' && buf[i] != '\0'; value[i] = buf[i], i++);

[...]

> 1) value[i] = buf[i]  will be done first

Also, that construct was probably done that way to shield one from
the undefined order of evaluation of value[i] and buf[i], as
value[i++] = buf[i] or value[i] = buf[i++] would be undefined.

-- 
Vincent Penquerc'h 
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