[LCP]Simple C test

[Andrew Weaver]

It does what you want. The problem is just that since stdout is buffered,
you don't see the output. Add fflush(stdout) between your printf and sleep.

On Thursday, July 04, 2002 9:31 AM, James Mclean [SMTP:james at adam.com.au]
wrote:
> 
> All,
> 
> I have written a small program to test out the \r carrige return.
> Perhaps i am missing the point, but it is not working as i would have
> thought.
> 
> This code below is used to count to 20, but in the one spot, rather then
> spaces between each line or on a new line.
> 
> if i use a \n rather than a \r it puts it on a new line, one at a time.
> what i want to see is each number ans it is incremented up to 20, rather
> than just 20, once it finishes its loop.
> 
> #include <stdio.h>
> #include <unistd.h>
> 
> int main(void) {
> 
>     int i;
> 
>     printf("\n");
> 
>     for(i = 1; i < 21; i++ ) {
>         printf("%d\r",i);
>         sleep(1);
>     }
> 
>     printf("\n");
> 
>     return 0;
> }
> 
> mabey i am missing something?
> 
> 
> 
> Regards,
> 
> James Mclean
> 
> "Increased knowledge will help you now.  
>  Have a mate's phone bugged."
> 		-- /usr/games/fortune
> 
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