[LCP]time 1e9

[Steve Fraser]

Hi Joachim,

Try setting the variable "now" to 2147483647.

This is about one fifth of your value (which had ten zeros!), and is also
the value defined for MAXLONG in values.h.

(time_t is a long)

Looks like Tue Jan 19 13:44:07 2038 will be a fun time in the Unix world!

cheers

Steve

PS with nine zeros (which is what I think you intended) your program gives
Sun Sep  9 11:16:40 2001.

PPS I always use -Wall on my compiles - it helps a lot :-)

----- Original Message -----
From: "Joachim Bauernberger" <bj at gmx.net>
To: <linuxCprogramming at lists.linux.org.au>
Sent: Friday, August 24, 2001 9:34 PM
Subject: [LCP]time 1e9


> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> Hi,
> I was wondering how i get the calendertime from the seconds as in:
>
> #include <time.h>
> #include <stdio.h>
>
> int main( int argc, char **argv) {
>
> /* soemwhen on the 9th of sept. 2001 unixtime will reach 1e9 */
>         time_t          now = 10000000000;
>
>         struct tm       *tt;
>         char *c;
>
>         tt = localtime(&now);
>         c = ctime(&now);
>
>         fprintf(stdout,"%d %d %d %d %d %d %d",tt->tm_sec, tt->tm_min,
> tt->tm_hour, tt->tm_mday, tt->tm_mon, tt->tm_year, tt->tm_wday);
>         fprintf(stdout,"\n%s\n",c);
>
> return 0;
> }
>
> This yields a date somewhen in 2014 Which isn't correct. Can somebody
please
> point out to me what I am missing.
>
> Thank's
> Joachim
>
> - --
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