#include<stdio.h>
main()
{
int a=555,*ptr=&a,b=*ptr;
printf("%d %d %d",++a,--b,(*ptr)++);
}
Answer:
for printf, arguments are evaluated
"right to left"
so, (*ptr)++
increments the value of a by 1. the current value of a will be 556, but
(*ptr) still outputs as 555
--b = 554 , as expected
++a = preincrementing
a = hence a will be 556 + 1 =557
hence the output!!
--------------------------------------
#include<stdio.h>
main()
{
int a=555,*ptr=&a,b=*ptr;
printf("%d %d %d",++a,--b,*ptr++);
}
Answer:
*ptr++ = postincrementing
the pointer ptr, hence the output will be 555
--b = 554 as expected.
++a= 556 , as expected!!
Thanks,
Murali.
"sowmya.k" <sowmi99@yahoo.com> Sent by: linuxcprogramming-admin@lists.linux.org.au
15/04/2004 06:46 PM
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Subject
[LCP]query regarding pointers
in C
pls tell me how these 2 pgms work
1. #include<stdio.h>
main()
{
int a=555,*ptr=&a,b=*ptr;
printf("%d %d %d",++a,--b,(*ptr)++);
}
for this the output is 557 554 555
2. #include<stdio.h>
main()
{
int a=555,*ptr=&a,b=*ptr;
printf("%d %d %d",++a,--b,*ptr++);
}
for this i got the output as 556 554 555
Could any one pls explain me the reson
behind this output